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QNEET-2024-Ph-65: NEET 2024 Physics - Class 11 NEET-2024-Ph-65 Solution: If \(x = 5 ( t + { }{3})\ {m}\) represents the motion of a…

If x=5sin⁡(πt+π3) mx = 5\sin(\pi t + \frac{\pi}{3})\ \text{m} represents the motion of a particle executing simple harmonic motion the amplitude and time period of motion respectively are 5 cm 2 s 5 m 2 s 5 cm 1 s 5 m 1 s

Multiple Choice Options

  • A 5 cm, 2 s
  • B 5 m, 2 s
  • C 5 cm, 1 s
  • D 5 m, 1 s

Step-by-Step Verified Solution

In the equation for simple harmonic motion (SHM), x = 5 sin _ ( � t + � 3 ) m , the general form x = A sin _ ( _ t + _ ) can be used to identify the parameters of SHM, where: A is the amplitude. _ (omega) is the angular frequency. _ (phi) is the phase constant. t is the time. Comparing the given equation with the standard form: The amplitude A is 5 m, as that is the coefficient of sine in the equation. The angular frequency _ is � rad/s. The angular frequency _ is related to the time period T of the motion through the formula: _ = 2 � T . Given that _ = � , we can substitute and solve for T : � = 2 � T _ T = 2 � � = 2  seconds . Hence, the amplitude of the motion is 5 m and the time period is 2 s. Thus, the correct answer is: Option B: 5 m, 2 s

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