QNEET-2024-Ph-63: NEET 2024 Physics - Class 12 NEET-2024-Ph-63 Solution: \(_{82}^{290}X Y + _{e}^{+} + _{Z}^{P}e + _{Q}\) In the nuclear …

To determine the mass number and atomic number of the final product Q in the provided nuclear reactions, we need to analyze the impact of each type of decay (alpha, positron emission, beta-minus decay, and electron capture) on the mass number and atomic number of the initial element X = 82 290 X : 1. Alpha decay ( _ decay): In alpha decay, an alpha particle (which is a 2 4 H e nucleus) is emitted. This reduces the mass number by 4 units and the atomic number by 2 units. 82 290 X _ _ 80 286 Y 2. Beta plus decay (positron emission, e + ): During positron emission, a proton in the nucleus is transformed into a neutron, and a positron is emitted. This decreases the atomic number by 1 but does not change the mass number. 80 286 Y _ e + 79 286 Z 3. Beta-minus decay ( _ _ decay): In a beta-minus decay, a neutron in the nucleus converts into a proton and an electron (beta particle) and an antineutrino are emitted. This results in an increase in the atomic number by 1, while the mass number remains unchanged. 79 286 Z _ _ _ 80 286 P 4. Electron capture ( e _ capture): During electron capture, an atomic electron is absorbed by the nucleus, causing a proton to convert into a neutron. This process decreases the atomic number by 1 without altering the mass number. 80 286 P _ e _ 79 286 Q From the calculations above, the mass number of Q is 286, and its atomic number is 79. Comparing these values with the multiple choices: Option A: Mass number = 280, Atomic number = 81 Option B: Mass number = 286, Atomic number = 80 Option C: Mass number = 288, Atomic number = 82 Option D: Mass number = 286, Atomic number = 81 None of these match exactly, implying an error in the problem or the answer options. Based on the correct atomic number calculations and assuming option D is meant to be atomic number 79, then the corrected choice would have been: D: Mass number = 286, Atomic number = 79