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QNEET-2024-Ph-52: NEET 2024 Physics - Class 12 NEET-2024-Ph-52 Solution: A \(10\ F\) capacitor is connected to a 210 V 50 Hz source as…
A capacitor is connected to a 210 V 50 Hz source as shown in figure. The peak current in the circuit is nearly (): 0.58 A 0.93 A 1.20 A 0.35 A
Multiple Choice Options
- A 0.58 A
- B 0.93 A
- C 1.20 A
- D 0.35 A
Step-by-Step Verified Solution
Capacitive Reactance
X C = 1 _ C = 1 2 � f C = 1 2 _ 3.14 _ 50 _ 10 _ 10 _ 6 = 1000 3.14
V rms = 210 V i rms = V rms X C = 210 X C Peak current = 2 i ms = 2 _ 210 1000 _ 3.14 = 0.932 = 0.93 A