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QNEET-2024-Ph-157: NEET 2024 Physics - Class 12 NEET-2024-Ph-157 Solution: If \( \) is the work function of photosensitive material in eV…

If ϕ\phi is the work function of photosensitive material in eV and light of wavelength of numerical value λ=hceϕ\lambda = \frac{hc}{e\phi} metre is incident on it with energy above its threshold value at an instant then the maximum kinetic energy of the photo-electron ejected by it at that instant (Take h-Planck's constant c-velocity of light in free space) is (in SI units): e+2ϕe + 2\phi 2e−ϕ2e - \phi e−ϕe - \phi e+ϕe + \phi

Multiple Choice Options

  • A e+2ϕe+2 \phi e + 2 _
  • B 2e−ϕ2 e-\phi 2 e _ _
  • C e−ϕe-\phi e _ _
  • D e+ϕe+\phi e + _

Step-by-Step Verified Solution

The energy of the incident light is given by: E = h _ = h c _ where h is Planck's constant, c is the speed of light, and _ is the wavelength of the light. Substituting the given value of _ , we get: E = h c h c / e = e The maximum kinetic energy of the photoelectron is given by: K E m a x = E _ _ where _ is the work function. Substituting the values, we get: K E m a x = e _ _ Therefore, the correct answer is Option C .

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