Verified Solution • 2025–26 Session moderate

QNEET-2024-Ph-156: NEET 2024 Physics - Class 11 NEET-2024-Ph-156 Solution: Let \( _1 _2\) and \( _3\) be the angular speed of the second…

Let ω1ω2\omega_1 \omega_2 and ω3\omega_3 be the angular speed of the second hand minute hand and hour hand of a smoothly running analog clock respectively. If x1x2x_1 x_2 and x3x_3 are their respective angular distances in 1 minute then the factor which remains constant (k) is x1/ω1=x2/ω2=x3/ω3=kx_1/\omega_1 = x_2/\omega_2 = x_3/\omega_3 = k ω1x1=ω2x2=ω3x3=k\omega_1 x_1 = \omega_2 x_2 = \omega_3 x_3 = k ω1x12=ω2x22=ω3x32=k\omega_1 x_1^2 = \omega_2 x_2^2 = \omega_3 x_3^2 = k ω12x1=ω22x2=ω32x3=k\omega_1^2 x_1 = \omega_2^2 x_2 = \omega_3^2 x_3 = k

Multiple Choice Options

  • A ω1x1=ω2x2=ω3x3=k\frac{\omega_1}{x_1}=\frac{\omega_2}{x_2}=\frac{\omega_3}{x_3}=k x 1 _ _ 1 _ _ = x 2 _ _ 2 _ _ = x 3 _ _ 3 _ _ = k
  • B ω1x1=ω2x2=ω3x3=k\omega_1 x_1=\omega_2 x_2=\omega_3 x_3=k _ 1 _ x 1 _ = _ 2 _ x 2 _ = _ 3 _ x 3 _ = k
  • C ω1x12=ω2x22=ω3x32=k\omega_1 x_1^2=\omega_2 x_2^2=\omega_3 x_3^2=k _ 1 _ x 1 2 _ = _ 2 _ x 2 2 _ = _ 3 _ x 3 2 _ = k
  • D ω12x1=ω22x2=ω32x3=k\omega_1^2 x_1=\omega_2^2 x_2=\omega_3^2 x_3=k _ 1 2 _ x 1 _ = _ 2 2 _ x 2 _ = _ 3 2 _ x 3 _ = k

Step-by-Step Verified Solution

_ 1 = 2 � 60 ; x 1 = 2 � 60 _ 60 = 2 � _ 2 = 2 � 3600 ; x 2 = 2 � 3600 _ 60 = 2 � 60 _ 3 = 2 � 3600 _ 12 ; x 3 = 2 � 3600 _ 12 _ 60 = 2 � 720 _ 1 x 1 = _ 2 x 2 = _ 3 x 3 = 1 60 = k

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