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QNEET-2024-Ph-147: NEET 2024 Physics - Class 11 NEET-2024-Ph-147 Solution: The radius of gyration of a solid sphere of mass 5 kg about XY…

The radius of gyration of a solid sphere of mass 5 kg about XY is 5 m as shown in figure. The radius of the sphere is

\sqrt{\frac{5x}{7}}\ \text{m}

then the value of x is: 5 2 3 5

Multiple Choice Options

A 5
B $\sqrt2$ 2 _
C $\sqrt3$ 3 _
D $\sqrt5$ 5 _

Step-by-Step Verified Solution

I X Y = I C M + M R 2 = 2 5 M R 2 + M R 2 = 7 5 M R 2 = 7 5 _ 5 R 2 = 7 R 2 .... (1) I X Y = M K 2 = 5 _ 5 2 � ( 2 ) _ 5 _ 5 2 = 7 _ R 2 [From (1) and (2)] _ R = 5 7 _ 5 = 5 x 7 (Given) _ x = 5

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