QNEET-2024-Ph-143: NEET 2024 Physics - Class 12 NEET-2024-Ph-143 Solution: A step up transformer is connected to an ac mains supply of 220 …

Let's analyze the problem step by step. We are given a step-up transformer with the following specifications: Primary Voltage (V p ) = 220   V Secondary Voltage (V s ) = 11000   V Power (P) = 88 watt The power input to the transformer is equal to the power output, assuming there is no loss in the transformer. Hence, P p r i m a r y = P s e c o n d a r y = P = 88   W The power equations can be written as: P p r i m a r y = V p I p P s e c o n d a r y = V s I s Given the power in the secondary winding is 88   W and the secondary voltage is 11000   V , we can find the secondary current I s using the formula: P s e c o n d a r y = V s I s Rearranging to solve for I s gives: I s = P V s Substituting the given values: I s = 88   W 11000   V Simplifying this expression: I s = 88 11000   A I s = 0.008   A I s = 8   mA Therefore, the current in the secondary circuit, ignoring the power loss in the transformer, is 8 mA . The correct option is Option A: 8 mA .