Verified Solution • 2025–26 Session moderate

QNEET-2024-Ph-136: NEET 2024 Physics - Class 11 NEET-2024-Ph-136 Solution: The pitch of an error free screw gauge is 1 mm and there are…

The pitch of an error free screw gauge is 1 mm and there are 100 divisions on the circular scale. While measuring the diameter of a thick wire the pitch scale reads 1 mm and 63rd division on the circular scale coincides with the reference line. The diameter of the wire is: 1.63 cm 0.163 cm 0.163 m 1.63 m

Multiple Choice Options

  • A 1.63 cm1.63 \mathrm{~cm} 1.63   cm
  • B 0.163 cm0.163 \mathrm{~cm} 0.163   cm
  • C 0.163 m0.163 \mathrm{~m} 0.163   m
  • D 1.63 m1.63 \mathrm{~m} 1.63   m

Step-by-Step Verified Solution

To determine the diameter of the wire using the screw gauge, we need to consider both the pitch scale reading and the circular scale reading. The formula to calculate the diameter is: D = P + ( C _ L ) Where: D is the diameter of the wire. P is the pitch scale reading. C is the circular scale reading. L is the least count of the screw gauge. Given: Pitch of the screw gauge, P = 1   mm Number of divisions on the circular scale = 100 Pitch scale reading, P = 1   mm The circular scale reads 63 rd division. First, we calculate the least count of the screw gauge: L = Pitch Number of divisions = 1   mm 100 = 0.01   mm Next, we substitute the values into the formula for the diameter: D = 1   mm + ( 63 _ 0.01   mm ) Calculate the product: 63 _ 0.01   mm = 0.63   mm Now, add the pitch scale reading and the circular scale reading: D = 1   mm + 0.63   mm = 1.63   mm Convert 1.63   mm to centimeters: 1.63   mm = 0.163   cm Therefore, the diameter of the wire is: Option B: 0.163   cm

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