Verified Solution • 2025–26 Session moderate

QNEET-2024-Ch-99: NEET 2024 Chemistry - Class 12 NEET-2024-Ch-99 Solution: Rate constants of a reaction at 500 K and 700 K are \(0.04\…

Rate constants of a reaction at 500 K and 700 K are 0.04 s−10.04\ \text{s}^{-1} and 0.14 s−10.14\ \text{s}^{-1} respectively; then activation energy of the reaction is: (Given: log⁡3.5=0.5441R=8.31 J K−1 mol−1\log 3.5 = 0.5441 R = 8.31\ \text{J}\ K^{-1}\ mol^{-1}) 182310 J 18500 J 18219 J 18030 J

Multiple Choice Options

  • A 182310 J
  • B 18500 J
  • C 18219 J
  • D 18030 J

Step-by-Step Verified Solution

K = A e _ E a / R T After taking In both side ln _ K = ln _ A _ E a R T ln _ K 1 = ln _ A _ E a R T 1 at temp. T 1 .... (i) ln _ K 2 = ln _ A _ E a R T 2 at temp. T 2 .... (ii)  (ii)  _  (i)  ln _ K 2 _ ln _ K 1 = E a R [ 1 T 1 _ 1 T 2 ] ln _ K 2 K 1 = E a R [ 1 500 _ 1 700 ] ln _ 0.14 0.04 = E a R [ 700 _ 500 500 _ 700 ] ln _ 14 4 = E a R [ 200 500 _ 700 ] log _ 3.5 = E a 2.303 _ R [ 1 250 _ 7 ] 0.5441 = E a 2.303 _ 8.31 [ 1 250 _ 7 ] E a = 0.5441 _ 8.31 _ 250 _ 7 _ 2.303 = 0.5441 _ 83.1 _ 25 _ 7 _ 2.303 = 18222.65 � 18219   J

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