QNEET-2024-Ch-95: NEET 2024 Chemistry - Class 11 NEET-2024-Ch-95 Solution: The amount of glucose required to prepare 250 mL of 20 M…

To find the amount of glucose required to prepare 250 mL of a M 20 aqueous solution, we need to follow these steps: 1. Convert the volume from milliliters to liters, because molarity is expressed in moles per liter (M). 2. Use the equation for molarity: M = n V where: M is the molarity (given as 1 20 M ) n is the number of moles of solute V is the volume of the solution in liters 3. Rearrange the equation to solve for the number of moles of glucose ( n ): n = M _ V 4. Convert the moles of glucose to grams using the molar mass of glucose. Let's proceed with the calculations: 1. Convert the volume to liters: 250 mL = 250 1000 L = 0.25 L 2. Calculate the moles of glucose: n = ( 1 20 ) _ 0.25 L = 0.25 20 mol = 0.0125 mol 3. Convert the moles of glucose to grams using the molar mass of glucose: mass = n _ molar mass mass = 0.0125 mol _ 180 g mol _ 1 = 2.25 g So, the amount of glucose required is: Option A: 2.25 g