QNEET-2024-Ch-89: NEET 2024 Chemistry - Class 11 NEET-2024-Ch-89 Solution: On complete combustion 0.3 g of an organic compound gave 0.2 g…

To determine the percentage composition of carbon and hydrogen in the organic compound, we need to calculate the amounts of carbon in CO 2 and hydrogen in H 2 O produced from the complete combustion of the compound. First, let's calculate the amount of carbon in CO 2 : The molar mass of CO 2 is 44 g/mol, and the molar mass of carbon (C) is 12 g/mol. Given that 0.2 g of CO 2 is produced, we can use the following proportion to find the mass of carbon: 12  g (C) 44  g (CO 2 ) = x 0.2  g (CO 2 ) Solving for x (mass of carbon): x = 12 _ 0.2 44 = 2.4 44 = 0.0545  g Next, let's calculate the amount of hydrogen in H 2 O: The molar mass of H 2 O is 18 g/mol, and the molar mass of hydrogen (H) in a single H 2 O molecule is 2 g/mol. Given that 0.1 g of H 2 O is produced, we can use the following proportion to find the mass of hydrogen: 2  g (H) 18  g (H 2 O ) = y 0.1  g (H 2 O ) Solving for y (mass of hydrogen): y = 2 _ 0.1 18 = 0.2 18 = 0.0111  g Now, we can calculate the percentage composition of carbon and hydrogen in the organic compound, which has a total mass of 0.3 g. Percentage of carbon: % C = ( 0.0545  g 0.3  g ) _ 100 = 18.18 % Percentage of hydrogen: % H = ( 0.0111  g 0.3  g ) _ 100 = 3.70 % Therefore, the correct answer is: Option B : 18.18% and 3.70%