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QNEET-2024-Ch-50: NEET 2024 Chemistry - Class 11 NEET-2024-Ch-50 Solution: Consider the following reaction in a sealed vessel at…

Consider the following reaction in a sealed vessel at equilibrium with concentrations of N2=3.0×10−3 MN_2 = 3.0 \times 10^{-3}\ \text{M} O2=4.2×10−3 MO_2 = 4.2 \times 10^{-3}\ \text{M} and NO=2.8×10−3 MNO = 2.8 \times 10^{-3}\ \text{M}. 2NO(g)⇌N2(g)+O2(g)2NO(g) \rightleftharpoons N_2(g) + O_2(g) If 0.1 mol L−10.1\ \text{mol L}^{-1} of NO(g)NO(g) is taken in a closed vessel what will be degree of dissociation (α\alpha) of NO(g)NO(g) at equilibrium? 0.00889 0.0889 0.8889 0.717

Multiple Choice Options

  • A 0.00889
  • B 0.0889
  • C 0.8889
  • D 0.717

Step-by-Step Verified Solution

2 NO ( g ) _ N 2 (   g ) + O 2 (   g ) K c = [ N 2 ] [ O 2 ] [ NO ] 2 = 3 _ 10 _ 3 _ 4.2 _ 10 _ 3 2.8 _ 10 _ 3 _ 2.8 _ 10 _ 3 = 1.607 K c = 0.05 _ _ 0.05 _ ( 0.1 _ 0.1 _ ) 2 K c = 0.05 _ _ 0.05 _ 0.01 ( 1 _ _ ) 2 1.607 = ( 0.05 ) 2 _ 2 0.01 ( 1 _ _ ) 2 _ 2 ( 1 _ _ ) 2 = 1.607 _ ( 0.1 ) 2 ( 0.05 ) 2 _ 1 _ _ = 1.27 _ 0.1 0.05 _ 1 _ _ = 2.54 _ = 2.54 _ 2.54 _ 3.54 _ = 2.54 _ = 2.54 3.54 = 0.717

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