QNEET-2024-Ch-41: NEET 2024 Chemistry - Class 12 NEET-2024-Ch-41 Solution: The Henry's law constant (\(K_H\)) values of three gases (A B…

According to Henry's law, the solubility of a gas in a liquid under constant temperature is directly proportional to the partial pressure of the gas above the liquid but is inversely proportional to the Henry's law constant ( K H ) for the gas. Henry's law can be expressed as: c = P K H where c is the concentration (or solubility) of the gas in the liquid, P is the partial pressure of the gas, and K H is Henry's law constant. From the equation, it is clear that the solubility of the gas is inversely related to K H ; if K H increases, the solubility decreases, and vice versa. In the given problem, you have the K H values of the gases A, B, and C as follows: A: 145 kbar B: 2 _ 10 _ 5   kbar C: 35 kbar Comparing the K H values: Gas B has the lowest K H and hence the highest solubility. Gas A, with the highest K H among the three, will have the lowest solubility. Gas C has a K H value less than A but greater than B, so its solubility will be lower than B but higher than A. Therefore, the order of solubility of the gases in water from the highest to the lowest is: B > C > A Thus, the correct option is: Option B: B > C > A