QNEET-2024-Ch-30: NEET 2024 Chemistry - Class 11 NEET-2024-Ch-30 Solution: The highest number of helium atoms is in 4 mol of helium 4u of…

To determine which option contains the highest number of helium atoms, we need to analyze each option based on the amount of helium it represents and apply Avogadro's Law as required. Option A: 4 mol of helium Using Avogadro's number, which is approximately 6.022 _ 10 23 atoms per mole, the number of helium atoms in 4 moles can be calculated as: 4 mol _ 6.022 _ 10 23 atoms/mol = 24.088 _ 10 23 atoms Option B: 4 u of helium The atomic mass of helium is approximately 4 u (atomic mass units). Therefore, 4 u represents about 1 mole of helium atoms (since the molar mass of helium is approximately 4 g/mol, which equals 4 u). Thus, this option represents: 1 mol _ 6.022 _ 10 23 atoms/mol = 6.022 _ 10 23 atoms Option C: 4 g of helium Similarly, as we've established that the molar mass of helium is 4 g/mol, 4 g of helium equates exactly to: 1 mol _ 6.022 _ 10 23 atoms/mol = 6.022 _ 10 23 atoms Option D: 2.271098 L of helium at STP (Standard Temperature and Pressure) At STP, one mole of any ideal gas occupies 22.4 L. Therefore, the amount of helium in moles for 2.271098 L can be derived from: 2.271098 L 22.4 L/mol � 0.101 mole Using this to find the number of atoms: 0.101 mol _ 6.022 _ 10 23 atoms/mol � 6.082 _ 10 22 atoms Conclusion: Comparing the numbers: Option A: 24.088 _ 10 23 atoms Option B: 6.022 _ 10 23 atoms Option C: 6.022 _ 10 23 atoms Option D: 6.082 _ 10 22 atoms Option A clearly contains the highest number of helium atoms, which is 24.088 _ 10 23 atoms .