Verified Solution • 2025–26 Session moderate

QNEET-2024-Ch-29: NEET 2024 Chemistry - Class 12 NEET-2024-Ch-29 Solution: The plot of osmotic pressure (\( \)) vs concentration (mol…

The plot of osmotic pressure (π\pi) vs concentration (mol L−1L^{-1}) for a solution gives a straight line with slope 25.73 L bar mol−1mol^{-1}. The temperature at which the osmotic pressure measurement is done is (Use R = 0.083 L bar mol−1K−1mol^{-1} K^{-1}) 37∘C37^\circ C 310∘C310^\circ C 25.73∘C25.73^\circ C 12.05∘C12.05^\circ C

Multiple Choice Options

  • A 37∘C37^{\circ} \mathrm{C} 3 7 _ C
  • B 310∘C310^{\circ} \mathrm{C} 31 0 _ C
  • C 25.73∘C25.73^{\circ} \mathrm{C} 25.7 3 _ C
  • D 12.05∘C12.05^{\circ} \mathrm{C} 12.0 5 _ C

Step-by-Step Verified Solution

The relationship between the osmotic pressure ( _ ) of a solution and its concentration ( c ) can be derived from the van't Hoff equation for dilute solutions, which is given by: _ = c R T where: _ is the osmotic pressure, c is the concentration of the solution in moles per liter, R is the ideal gas constant in appropriate units, and T is the temperature in Kelvin. According to the problem, the slope of the _ vs c plot is given as 25.73   L   bar   mol _ 1 which corresponds to the product R T from the van't Hoff equation. We are provided with the value of the gas constant R = 0.083   L   bar   mol _ 1   K _ 1 . To find the temperature T , we use the following equation derived from the slope of the line: R T = 25.73   L   bar   mol _ 1 To isolate T , we rearrange the equation: T = 25.73   L   bar   mol _ 1 0.083   L   bar   mol _ 1   K _ 1 � 310   K To convert this temperature from Kelvin to Celsius, we use the conversion formula: T Celsius = T Kelvin _ 273.15 T Celsius = 310   K _ 273.15 � 36.85 _ C This value is closest to 37 _ C , which corresponds to Option A. Therefore, the temperature at which the osmotic pressure measurement is done is approximately 37 _ C .

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