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QNEET-2024-Ch-16: NEET 2024 Chemistry - Class 11 NEET-2024-Ch-16 Solution: A compound X contains 32% of A 20% of B and remaining…

A compound X contains 32% of A 20% of B and remaining percentage of C. Then the empirical formula of X is: (Given atomic masses of A=64; B=40; C=32 u) A2BC2A_2BC_2 ABC3ABC_3 AB2C2AB_2C_2 ABC4ABC_4

Multiple Choice Options

  • A A2BC2\mathrm{A}_2 \mathrm{BC}_2 A 2 _ BC 2 _
  • B ABC3\mathrm{ABC}_3 ABC 3 _
  • C AB2C2\mathrm{AB}_2 \mathrm{C}_2 AB 2 _ C 2 _
  • D ABC4\mathrm{ABC}_4 ABC 4 _

Step-by-Step Verified Solution

.tg {border-collapse:collapse;border-spacing:0;} .tg td{border-color:black;border-style:solid;border-width:1px;font-family:Arial, sans-serif;font-size:14px; overflow:hidden;padding:10px 5px;word-break:normal;} .tg th{border-color:black;border-style:solid;border-width:1px;font-family:Arial, sans-serif;font-size:14px; font-weight:normal;overflow:hidden;padding:10px 5px;word-break:normal;} .tg .tg-c3ow{border-color:inherit;text-align:center;vertical-align:top} .tg .tg-7btt{border-color:inherit;font-weight:bold;text-align:center;vertical-align:top} Element | Mass percentage % | No. of moles | No. of moles/Smallest number | Simplest whole number A | 32% | 32 64 = 1 2 | 1 2 _ 2 | = 1 B | 20% | 20 40 = 1 2 | 1 2 _ 2 | = 1 C | 48% | 48 32 = 3 2 | 3 2 _ 2 | = 3 So, empirical formula of _  The correct empirical formula of compound  X  is  ABC 3

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