Verified Solution • 2025–26 Session
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QNEET-2024-Ch-116: NEET 2024 Chemistry - Class 12 NEET-2024-Ch-116 Solution: Match List I with List II: List - I (Block/group in periodic…
Match List I with List II: List - I (Block/group in periodic table) List - II (Element) (A) Lanthanoid (I) Ce (B) d-block element (II) As (C) p-block element (III) Cs (D) s-block element (IV) Mn Choose the correct answer from the options given below
Multiple Choice Options
- A A-I, B-II, C-IV, D-III
- B A-I, B-IV, C-III, D-II
- C A-I, B-IV, C-II, D-III
- D A-IV, B-I, C-II, D-III
Step-by-Step Verified Solution
Let's match each element in List II with the appropriate block or group in List I:
(A) Lanthanoid - The Lanthanides or Lanthanoids are a series of 15 metallic elements from Lanthanum (La) to Lutetium (Lu). Cerium (Ce) is part of this series.
(B) d-block element - The d-block elements are also known as transition metals. Manganese (Mn) belongs to this group.
(C) p-block element - The p-block contains elements from groups 13 to 18 of the periodic table; Arsenic (As) belongs to this block.
(D) s-block element - The s-block elements include the first two groups (alkali metals and alkaline earth metals). Cesium (Cs) is one of the alkali metals, hence it is part of the s-block.
So, the correct matching is:
(A) Lanthanoid - (I) Ce
(B) d-block element - (IV) Mn
(C) p-block element - (II) As
(D) s-block element - (III) Cs
Thus, the correct option is Option C:
A-I, B-IV, C-II, D-III