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QNEET-2024-Ch-114: NEET 2024 Chemistry - Class 12 NEET-2024-Ch-114 Solution: Mass of glucose (\(C_6H_{12}O_6\)) required to be dissolved to…
Mass of glucose () required to be dissolved to prepare one litre of its solution which is isotonic with solution of urea () is (Given: Molar mass in g C:12 H:1 O:16 N:14) 55 g 15 g 30 g 45 g
Multiple Choice Options
- A 55 g
- B 15 g
- C 30 g
- D 45 g
Step-by-Step Verified Solution
For isotonic solutions [osmotic pressure must be equal]
� 1 = � 2 C 1 R T = C 2 R T C 1 = C 2 m 180 _ 1 = 15 60 _ 1 ( m is the mass of glucose) m = 180 4 = 45 g