Verified Solution • 2025–26 Session
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QNEET-2024-Ch-110: NEET 2024 Chemistry - Class 11 NEET-2024-Ch-110 Solution: At a given temperature and pressure the equilibrium constant…
At a given temperature and pressure the equilibrium constant values for the equilibria are given below: The relation between and is:
Multiple Choice Options
- A K 1 2 _ = 2 K 2 _
- B K 2 _ = 2 K 1 _ _
- C K 1 _ = K 2 _ _ 1 _
- D K 2 _ = K 1 _ _ 1 _
Step-by-Step Verified Solution
To find the relationship between K 1 and K 2 , let's carefully analyze the given equilibrium reactions and their constants.
First, let's write down the equilibrium reactions clearly:
Reaction 1: 3 A 2 + B 2 _ 2 A 3 B with equilibrium constant K 1 .
Reaction 2: A 3 B _ 3 2 A 2 + 1 2 B 2 with equilibrium constant K 2 .
Now, understand that K 2 represents the equilibrium constant of the reverse reaction of Reaction 1 but with both sides divided by 2. We need to relate these constants. Here is the step-by-step process:
We know Reaction 1 is: 3 A 2 + B 2 _ 2 A 3 B .
The equilibrium constant for Reaction 1 is: K 1 = [ A 3 B ] 2 [ A 2 ] 3 [ B 2 ] .
For Reaction 2: A 3 B _ 3 2 A 2 + 1 2 B 2 , the equilibrium constant K 2 can be expressed as the equilibrium constant of the reverse of Reaction 1, with adjusted coefficients.
The equilibrium constant for the reverse reaction of Reaction 1 would be 1 K 1 . Since Reaction 2 includes halving the coefficients, the equilibrium constant should be adjusted by taking the square root:
K 2 = ( 1 K 1 ) 1 / 2 = 1 K 1 .
Therefore, the relationship between K 1 and K 2 is:
Option D: K 2 = 1 K 1 .