Verified Solution • 2025–26 Session moderate

QNEET-2024-Ch-11: NEET 2024 Chemistry - Class 11 NEET-2024-Ch-11 Solution: In which of the following equilibria \(K_p\) and \(K_c\) are…

In which of the following equilibria KpK_p and KcK_c are NOT equal? PCl5(g)⇌PCl3(g)+Cl2(g)PCl_5(g) \rightleftharpoons PCl_3(g) + Cl_2(g) H2(g)+I2(g)⇌2HI(g)H_2(g) + I_2(g) \rightleftharpoons 2HI(g) CO(g)+H2O(g)⇌CO2(g)+H2(g)CO(g) + H_2O(g) \rightleftharpoons CO_2(g) + H_2(g) 2BrCl(g)⇌Br2(g)+Cl2(g)2BrCl(g) \rightleftharpoons Br_2(g) + Cl_2(g)

Multiple Choice Options

  • A PCl5( g)⇌PCl3( g)+Cl2( g)\mathrm{PCl}_{5(\mathrm{~g})} \rightleftharpoons \mathrm{PCl}_{3(\mathrm{~g})}+\mathrm{Cl}_{2(\mathrm{~g})} PCl 5 (   g ) _ _ PCl 3 (   g ) _ + Cl 2 (   g ) _
  • B H2( g)+I2( g)⇌2HI(g)\mathrm{H}_{2(\mathrm{~g})}+\mathrm{I}_{2(\mathrm{~g})} \rightleftharpoons 2 \mathrm{HI}_{(\mathrm{g})} H 2 (   g ) _ + I 2 (   g ) _ _ 2 HI ( g ) _
  • C CO(g)+H2O(g)⇌CO2( g)+H2( g)\mathrm{CO}_{(\mathrm{g})}+\mathrm{H}_2 \mathrm{O}_{(\mathrm{g})} \rightleftharpoons \mathrm{CO}_{2(\mathrm{~g})}+\mathrm{H}_{2(\mathrm{~g})} CO ( g ) _ + H 2 _ O ( g ) _ _ CO 2 (   g ) _ + H 2 (   g ) _
  • D 2BrCl(g)⇌Br2( g)+Cl2( g)2 \mathrm{BrCl}_{(\mathrm{g})} \rightleftharpoons \mathrm{Br}_{2(\mathrm{~g})}+\mathrm{Cl}_{2(\mathrm{~g})} 2 BrCl ( g ) _ _ Br 2 (   g ) _ + Cl 2 (   g ) _

Step-by-Step Verified Solution

To determine in which of the given equilibria K p and K c are not equal, it's important to understand the relationship between these two equilibrium constants. This relationship is expressed by the equation: K p = K c ( R T ) _ n where R is the gas constant, T is the temperature in Kelvin, and _ n is the change in the number of moles of gas (number of moles of gaseous products minus number of moles of gaseous reactants). If _ n = 0 , then K p and K c are equal because ( R T ) 0 = 1 . However, if _ n � 0 , the constants will not be the same, and the degree to which they differ will depend on the temperature and the value of _ n . Now, let's analyze each option: Option A: PCl 5 (   g ) _ PCl 3 (   g ) + Cl 2 (   g ) Reactant side moles = 1, Product side moles = 2; _ n = 2 _ 1 = 1 . Option B: H 2 (   g ) + I 2 (   g ) _ 2 HI ( g ) Reactant side moles = 2, Product side moles = 2; _ n = 2 _ 2 = 0 . Option C: CO ( g ) + H 2 O ( g ) _ CO 2 (   g ) + H 2 (   g ) Reactant side moles = 2, Product side moles = 2; _ n = 2 _ 2 = 0 . Option D: 2 BrCl ( g ) _ Br 2 (   g ) + Cl 2 (   g ) Reactant side moles = 2, Product side moles = 2; _ n = 2 _ 2 = 0 . From this analysis, it is evident that K p and K c are not equal in Option A where _ n = 1 . In all other options, since _ n = 0 , K p is equal to K c . Thus, the correct answer is Option A.

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