QNEET-2024-Ch-102: NEET 2024 Chemistry - Class 11 NEET-2024-Ch-102 Solution: 1.0 g of \(H_2\) has same number of molecules as in: 14 g of…

To determine which of the given options contains the same number of molecules as 1.0   g of H 2 , we need to use the concept of moles and Avogadro's number. First, let's calculate the number of moles in 1.0   g of H 2 . The molar mass of H 2 is 2   g / mol . Therefore, the number of moles of H 2 in 1.0   g can be calculated as: Number of moles of  H 2 = Mass Molar Mass = 1.0   g 2   g / mol = 0.5   mol Next, we need to find out which of the given options corresponds to the same number of moles. Let's calculate the number of moles for each option: Option A: 14   g  of  N 2 . The molar mass of N 2 is 28   g / mol . The number of moles of N 2 in 14   g is: Number of moles of  N 2 = 14   g 28   g / mol = 0.5   mol Option B: 18   g  of  H 2 O . The molar mass of H 2 O is 18   g / mol . The number of moles of H 2 O in 18   g is: Number of moles of  H 2 O = 18   g 18   g / mol = 1   mol Option C: 16   g  of  CO . The molar mass of CO is 28   g / mol . The number of moles of CO in 16   g is: Number of moles of  CO = 16   g 28   g / mol = 0.571   mol Option D: 28   g  of  N 2 . The molar mass of N 2 is 28   g / mol . The number of moles of N 2 in 28   g is: Number of moles of  N 2 = 28   g 28   g / mol = 1   mol Comparing these calculated values, we can see that 0.5   mol of N 2 (Option A) is equal to 0.5   mol of H 2 . Therefore, the correct answer is: Option A: 14   g of N 2 .