QNEET-2024-Ch-1: NEET 2024 Chemistry - Class 11 NEET-2024-Ch-1 Solution: For the reaction \(2A B + C\) \(K_c = 4 10^{-3}\). At a given…

Step-by-Step Calculation

1. Calculate the reaction quotient ($Q_c$): For the balanced equilibrium:
2. $$2\text{A} \rightleftharpoons \text{B} + \text{C}$$
3. The expression for the reaction quotient is:
4. $$Q_c = \frac{[\text{B}][\text{C}]}{[\text{A}]^2}$$
5. Substitute the given concentrations:
6. $$Q_c = \frac{(2 \times 10^{-3})(2 \times 10^{-3})}{(2 \times 10^{-3})^2} = \frac{4 \times 10^{-6}}{4 \times 10^{-6}} = 1$$
7. Compare $Q_c$ with $K_c$:
8. $Q_c = 1$
9. $K_c = 4 \times 10^{-3}$
10. Since Q_c > K_c, the concentration of products is higher than at equilibrium. To achieve equilibrium, the system will shift to the left, consuming products to form reactants.

Therefore, the reaction has a tendency to proceed in the backward direction.