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QNEET-2023-Ph-363: NEET 2023 Physics - Class 12 NEET-2023-Ph-363 Solution: The angular momentum of an electron moving in an orbit of…

The angular momentum of an electron moving in an orbit of hydrogen atom is 1.5(hπ)1.5(\frac{h}{\pi}). The energy in the same orbit is nearly. -1.5 eV -1.6 eV -1.3 eV -1.4 eV

Multiple Choice Options

  • A −1.5-1.5 _ 1.5 eV
  • B −1.6-1.6 _ 1.6 eV
  • C −1.3-1.3 _ 1.3 eV
  • D −1.4-1.4 _ 1.4 eV

Step-by-Step Verified Solution

The given angular momentum of the electron is 1.5 ( h � ) , where h hh h is Planck's constant. According to the Bohr model of the hydrogen atom, the allowed angular momenta for an electron are quantized and given by m v r = n h 2 � where m mm m is the mass of the electron, v vv v is its velocity, r rr r is the radius of the orbit, and n nn n is the principal quantum number (an integer). By comparing the given angular momentum with the quantized form, we get 1.5 h � = n h 2 � , which simplifies to n = 3 . Now, we use the formula for the energy levels of the hydrogen atom: E n = _ 13.6 eV n 2 . Since n = 3 n=3n = 3 n = 3 , the energy can be calculated as E 3 = _ 13.6 eV 3 2 , which is approximately _ 1.5 eV .

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