Verified Solution • 2025–26 Session moderate

QNEET-2023-Ph-349: NEET 2023 Physics - Class 11 NEET-2023-Ph-349 Solution: A simple pendulum oscillating in air has a period of \( {3}\…

A simple pendulum oscillating in air has a period of 3 s\sqrt{3}\ \text{s}. If it is completely immersed in non-viscous liquid having density (14)(\frac{1}{4})th of the material of the bob the new period will be :- 23 s2\sqrt{3}\ \text{s} 23 s\sqrt{\frac{2}{3}}\ \text{s} 2 s 32 s\sqrt{\frac{3}{2}}\ \text{s}

Multiple Choice Options

  • A 232 \sqrt{3} 2 3 _ s
  • B 23 s\frac{2}{\sqrt{3}} \mathrm{~s} 3 _ 2 _   s
  • C 2 s2 \mathrm{~s} 2   s
  • D 32 s\frac{\sqrt{3}}{2} \mathrm{~s} 2 3 _ _   s

Step-by-Step Verified Solution

T air  = 2 � _ g = 3   sec ln _  Liquid  _ g net  = g ( 1 _ _ _ ) _ =  density of liquid  _ =  density of material of bob   so  T Liq  = 2 � ( _ g net  ) = 2 � _ g ( 1 _ _ _ ) T Liq  = T air  1 _ _ _ = 3 1 _ 1 4 = 3 3 2 = 2   sec

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