Verified Solution • 2025–26 Session moderate

QNEET-2023-Ph-317: NEET 2023 Physics - Class 11 NEET-2023-Ph-317 Solution: The viscous drag acting on a metal sphere of diameter 1 mm…

The viscous drag acting on a metal sphere of diameter 1 mm falling through a fluid of viscosity 0.8 Pa s with a velocity of 2 m s−12\ \text{m s}^{-1} is equal to: 15×10−3 N15 \times 10^{-3}\ \text{N} 30×10−3 N30 \times 10^{-3}\ \text{N} 1.5×10−3 N1.5 \times 10^{-3}\ \text{N} 20×10−3 N20 \times 10^{-3}\ \text{N}

Multiple Choice Options

  • A 15×10−3 N15 \times 10^{-3} \mathrm{~N} 15 _ 1 0 _ 3   N
  • B 30×10−3 N30 \times 10^{-3} \mathrm{~N} 30 _ 1 0 _ 3   N
  • C 1.5×10−3 N1.5 \times 10^{-3} \mathrm{~N} 1.5 _ 1 0 _ 3   N
  • D 20×10−3 N20 \times 10^{-3} \mathrm{~N} 20 _ 1 0 _ 3   N

Step-by-Step Verified Solution

F = 6 � r _ v = ( 6 ) ( 3.14 ) ( 1 _ 10 _ 3 2 ) ( 0.8 _ 10 _ 1 ) ( 2 ) = 1.5 _ 10 _ 3   N

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