Verified Solution • 2025–26 Session moderate

QNEET-2023-Ph-269: NEET 2023 Physics - Class 12 NEET-2023-Ph-269 Solution: An electric dipole is placed as shown in the figure. The…

An electric dipole is placed as shown in the figure. The electric potential (in 102 V10^2\ \text{V}) at point P due to the dipole is (ϵ0\epsilon_0 = permittivity of free space and 14πϵ0=K\frac{1}{4\pi\epsilon_0} = K): (58)qK(\frac{5}{8})qK (85)qK(\frac{8}{5})qK (83)qK(\frac{8}{3})qK (38)qK(\frac{3}{8})qK

Multiple Choice Options

  • A (58)qK\left(\frac{5}{8}\right) \mathrm{qK} ( 8 5 _ ) qK
  • B (85)qK\left(\frac{8}{5}\right) \mathrm{qK} ( 5 8 _ ) qK
  • C (83)qK\left(\frac{8}{3}\right) \mathrm{qK} ( 3 8 _ ) qK
  • D (38)qK\left(\frac{3}{8}\right) \mathrm{qK} ( 8 3 _ ) qK

Step-by-Step Verified Solution

v = Kq 2 _ 10 _ 2 _ Kq 8 _ 10 _ 2 = Kq [ 3 8 ] _ 10 2

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