QNEET-2023-Ph-256: NEET 2023 Physics - Class 12 NEET-2023-Ph-256 Solution: An electric dipole is placed at an angle of \(30^ \) with an…

The torque _ experienced by an electric dipole in an electric field is given by the formula: _ = p E sin _ _ where p is the electric dipole moment, E is the electric field intensity, and _ is the angle between the dipole and the electric field. The electric dipole moment p can be expressed as: p = q d where q is the charge on the dipole, and d is the dipole length. We are given the following values: Torque _ = 4 N�m Electric field intensity E = 2 _ 10 5   NC _ 1 Angle _ = 30 _ Dipole length d = 2 cm = 0.02 m We need to find the charge q on the dipole. Let's first solve for the electric dipole moment p: _ = p E sin _ _ _ p = _ E sin _ _ Substituting the given values: p = 4 ( 2 _ 10 5 ) sin _ 30 _ = 4 ( 2 _ 10 5 ) ( 0.5 ) = 4 10 5 = 4 _ 10 _ 5   C   m Now, let's solve for the charge q using the formula: _ p = q d q = p d Substituting the values for p and d: q = 4 _ 10 _ 5 0.02 = 2 _ 10 _ 3   C = 2   mC So, the magnitude of the charge on the dipole is 2 mC.