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QNEET-2023-Ph-249: NEET 2023 Physics - Class 11 NEET-2023-Ph-249 Solution: Two bodies of mass m and 9m are placed at a distance R. The…

Two bodies of mass m and 9m are placed at a distance R. The gravitational potential on the line joining the bodies where the gravitational field equals zero will be (G = gravitational constant):

-\frac{12Gm}{R}

-\frac{16Gm}{R}

-\frac{20Gm}{R}

-\frac{8Gm}{R}

Multiple Choice Options

A $-\frac{12 G m}{R}$ _ R 12 G m _
B $-\frac{16 G m}{R}$ _ R 16 G m _
C $-\frac{20 G m}{R}$ _ R 20 G m _
D $-\frac{8 G m}{R}$ _ R 8 G m _

Step-by-Step Verified Solution

Position of Neutral point (Zero Gravitational Field) r 1 = m 1 R m 1 + m 2 = m R m + 9 m = R 4 r 2 = R _ R / 4 = 3 R / 4 Now Gravitational potential at point P V P = _ G M R / 4 _ 9 ( GM ) 3 R / 4 = _ 16 GM R

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