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QNEET-2023-Ph-248: NEET 2023 Physics - Class 12 NEET-2023-Ph-248 Solution: The minimum wavelength of X-rays produced by an electron…

The minimum wavelength of X-rays produced by an electron accelerated through a potential difference of V volts is proportional to: 1V\frac{1}{V} V\sqrt{V} 1V\frac{1}{\sqrt{V}} V2V^2

Multiple Choice Options

  • A 1V\frac{1}{V} V 1 _
  • B 1V\frac{1}{\sqrt{V}} V _ 1 _
  • C V2V^{2} V 2
  • D V\sqrt{V} V _

Step-by-Step Verified Solution

The minimum wavelength, _ min , of X-rays produced by an electron can be determined using the equation derived from the energy of a photon and the energy given to an electron by an accelerating voltage, V . The energy of a photon is given by E = h c / _ , where h is Planck's constant, c is the speed of light, and _ is the wavelength of the photon. When an electron is accelerated through a potential difference of V volts, it gains kinetic energy equal to e V , where e is the electron charge. This energy is then converted into a photon's energy when the electron collides with a target in an X-ray tube, resulting in X-rays of wavelength _ . Setting the kinetic energy equal to the photon energy gives e V = h c / _ . Solving for _ gives _ = h c / ( e V ) . Therefore, the minimum wavelength (corresponding to the maximum energy photon produced when all the kinetic energy is converted into photon energy) is inversely proportional to the voltage, V . Thus, _ min _ 1 / V .

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