Verified Solution • 2025–26 Session moderate

QNEET-2023-Ph-227: NEET 2023 Physics - Class 12 NEET-2023-Ph-227 Solution: The magnetic energy stored in an inductor of inductance \(4 H\) …

The magnetic energy stored in an inductor of inductance 4μH4\mu H carrying a current of 2 A is: 4 mJ 8 mJ 8 μJ\mu J 4 μJ\mu J

Multiple Choice Options

  • A 4 mJ4 \mathrm{~mJ} 4   mJ
  • B 8 mJ8 \mathrm{~mJ} 8   mJ
  • C 8 μJ8 ~\mu \mathrm{J} 8   _ J
  • D 4 μJ4 ~\mu \mathrm{J} 4   _ J

Step-by-Step Verified Solution

The formula for calculating the magnetic energy stored in an inductor is given by: E = 1 2 L I 2 where: E is the energy stored (in joules, J), L is the inductance of the inductor (in henrys, H), I is the current flowing through the inductor (in amperes, A). Plugging the given values into the formula: E = 1 2 _ 4 _ H _ ( 2 A ) 2 E = 1 2 _ 4 _ 10 _ 6 H _ 4 A 2 E = 2 _ 10 _ 6 H _ 4 E = 8 _ 10 _ 6 J Hence, the energy stored in the inductor is 8 _ J .

Related Learning Resources & Exam Preparation