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QNEET-2022-Ph-540: NEET 2022 Physics - Class 12 NEET-2022-Ph-540 Solution: The magnetic flux linked to a circular coil of radius R is \( = …

The magnetic flux linked to a circular coil of radius R is ϕ=2t3+4t2+2t+5 Wb\phi = 2t^3 + 4t^2 + 2t + 5\ \text{Wb} The magnitude of induced emf in the coil at t = 5 s is 192 V 108 V 197 V 150 V

Multiple Choice Options

  • A 192 V
  • B 108 V
  • C 197 V
  • D 150 V

Step-by-Step Verified Solution

Given magnetic flux is _ = 2 t 3 + 4 t 2 + 2 t + 5 Induced emf is given by _ = _ d _ d t = _ d d t ( 2 t 3 + 4 t 2 + 2 t + 5 ) | _ | = 6 t 2 + 8 t + 2 At t = 5 s, | _ | = 6 _ 25 + 8 _ 5 + 2 = 150 + 40 + 2 = 192 V

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