Verified Solution • 2025–26 Session moderate

QNEET-2022-Ph-532: NEET 2022 Physics - Class 12 NEET-2022-Ph-532 Solution: The magnetic field on the axis of a circular loop of radius 100 …

The magnetic field on the axis of a circular loop of radius 100 cm carrying current I=2 AI = \sqrt{2}\ \text{A} at point 1 m away from the centre of the loop is given by: 6.28×10−4 T6.28 \times 10^{-4}\ \text{T} 3.14×10−7 T3.14 \times 10^{-7}\ \text{T} 6.28×10−7 T6.28 \times 10^{-7}\ \text{T} 3.14×10−4 T3.14 \times 10^{-4}\ \text{T}

Multiple Choice Options

  • A 6.28×10−46.28 \times {10^{ - 4}} 6.28 _ 1 0 _ 4 T
  • B 3.14×10−73.14 \times {10^{ - 7}} 3.14 _ 1 0 _ 7 T
  • C 6.28×10−76.28 \times {10^{ - 7}} 6.28 _ 1 0 _ 7 T
  • D 3.14×10−43.14 \times {10^{ - 4}} 3.14 _ 1 0 _ 4 T

Step-by-Step Verified Solution

Magnetic field at the axis of a current carrying circular loop | B | = _ 0 i a 2 2 [ a 2 + d 2 ] 3 / 2 _ | B | = 4 � _ 10 _ 7 _ 2 _ 1 2 [ 1 + 1 ] 3 / 2 | B | = 4 � _ 10 _ 7 _ 2 2. ( 2 ) 3 / 2 = 4 � _ 10 _ 7 ( 2 ) 3 / 2 _ ( 2 ) 1 / 2 = 3.14 _ 10 _ 7 T

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