Verified Solution • 2025–26 Session moderate

QNEET-2022-Ph-529: NEET 2022 Physics - Class 12 NEET-2022-Ph-529 Solution: A cell of emf 4 V and internal resistance \(0.5 \) is connected …

A cell of emf 4 V and internal resistance 0.5Ω0.5\Omega is connected to a 7.5Ω7.5\Omega external resistance. The terminal potential difference of the cell is 0.375 V 3.75 V 4.25 V 4 V

Multiple Choice Options

  • A 0.375 V
  • B 3.75 V
  • C 4.25 V
  • D 4 V

Step-by-Step Verified Solution

From Kirchhoff's loop law : V _ I r _ I R = 0 _ I = ( V r + R ) Terminal potential difference across cell, V A B = I R V A B = R V r + R = 7.5 _ 4 0.5 + 7.5 = 3.75 V

Related Learning Resources & Exam Preparation