Verified Solution • 2025–26 Session moderate

QNEET-2022-Ph-526: NEET 2022 Physics - Class 12 NEET-2022-Ph-526 Solution: Two very long straight parallel conductors A and B carry…

Two very long straight parallel conductors A and B carry current of 5 A and 10 A respectively and are at a distance of 10 cm from each other. The direction of current in two conductors is same. The force acting per unit length between two conductors is: (μ0=4π×10−7 SI unit\mu_0 = 4\pi \times 10^{-7}\ \text{SI unit}) 1×10−4 Nm−11 \times 10^{-4}\ \text{Nm}^{-1} and is repulsive 2×10−4 Nm−12 \times 10^{-4}\ \text{Nm}^{-1} and is attractive 2×10−4 Nm−12 \times 10^{-4}\ \text{Nm}^{-1} and is repulsive 1×10−4 Nm−11 \times 10^{-4}\ \text{Nm}^{-1} and is attractive

Multiple Choice Options

  • A 1 ×\times _ 10 −- _ 4 Nm −- _ 1 and is repulsive
  • B 2 ×\times _ 10 −- _ 4 Nm −- _ 1 and is attractive
  • C 2 ×\times _ 10 −- _ 4 Nm −- _ 1 and is repulsive
  • D 1 ×\times _ 10 −- _ 4 Nm −- _ 1 and is attractive

Step-by-Step Verified Solution

Force per unit length between two long current carrying wires = _ 0 l 1 l 2 2 � d F = 4 � _ 10 _ 7 _ 5 _ 10 2 � _ 10 _ 10 _ 2 = 10 _ 4 Nm _ 1 _ The force is attractive as direction of current in two conductors is same Hence, required force is 1 _ 10 _ 4 Nm _ 1 and it is attractive.

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