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QNEET-2022-Ph-457: NEET 2022 Physics - Class 11 NEET-2022-Ph-457 Solution: An electric lift with a maximum load of 2000 kg (lift +…
An electric lift with a maximum load of 2000 kg (lift + passengers) is moving up with a constant speed of 1.5 m. The frictional force opposing the motion is 3000 N. The minimum power delivered by the motor to the lift in watts is: (g = 10 m) 23000 20000 34500 23500
Multiple Choice Options
- A 23000
- B 20000
- C 34500
- D 23500
Step-by-Step Verified Solution
F up = 2000 g + 3000
= 23000 N
Minimum power P min = F _ . v _
P min = Fv = 23000 _ 3 2
= 34500 W