Verified Solution • 2025–26 Session moderate

QNEET-2022-Ph-444: NEET 2022 Physics - Class 12 NEET-2022-Ph-444 Solution: In the given nuclear reaction the element X is \(_{11}^{22}Na X …

In the given nuclear reaction the element X is 1122Na→X+e++ν_{11}^{22}Na \rightarrow X + e^+ + \nu 1123Na_{11}^{23}Na 1023Ne_{10}^{23}Ne 1022Ne_{10}^{22}Ne 1222Mg_{12}^{22}Mg

Multiple Choice Options

  • A 1123Na{}_{11}^{23}Na 11 23 _ N a
  • B 1023Ne{}_{10}^{23}Ne 10 23 _ N e
  • C 1022Ne{}_{10}^{22}Ne 10 22 _ N e
  • D 1222Mg{}_{12}^{22}Mg 12 22 _ M g

Step-by-Step Verified Solution

The nuclear reaction is given as 11 22 N a _ Z A X + + 1 e 0 + v From conservation of atomic number 11 = Z + 1 _ Z = 10 _ N e From conservation of mass number 22 = A + 0 _ A = 22 _ Z A X = 10 22 N e

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