Verified Solution • 2025–26 Session moderate

QNEET-2022-Ph-416: NEET 2022 Physics - Class 12 NEET-2022-Ph-416 Solution: A capacitor of capacitance C = 900 pF is charged fully by 100 V …

A capacitor of capacitance C = 900 pF is charged fully by 100 V battery B as shown in figure (a). Then it is disconnected from the battery and connected to another uncharged capacitor of capacitance C = 900 pF as shown in figure (b). The electrostatic energy stored by the system (b) is 4.5×10−6 J4.5 \times 10^{-6}\ \text{J} 3.25×10−6 J3.25 \times 10^{-6}\ \text{J} 2.25×10−6 J2.25 \times 10^{-6}\ \text{J} 1.5×10−6 J1.5 \times 10^{-6}\ \text{J}

Multiple Choice Options

  • A 4.5 ×\times _ 10 −- _ 6 J
  • B 3.25 ×\times _ 10 −- _ 6 J
  • C 2.25 ×\times _ 10 −- _ 6 J
  • D 1.5 ×\times _ 10 −- _ 6 J

Step-by-Step Verified Solution

q 1 = CV = 900 _ 10 _ 12 _ 100 = 9 _ 10 _ 8 C V = C 1 V 1 + C 2 V 2 C 1 + C 2 = 9 _ 10 _ 8 + 0 1800 _ 10 _ 12 = 100 2 = 50 V U = 1 2 ( C 1 + C 2 ) V 2 = 1 2 _ 1800 _ 10 _ 12 _ 50 _ 50 = 225 _ 10 _ 8 U = 2.25 _ 10 _ 6 J

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