Verified Solution • 2025–26 Session moderate

QNEET-2022-Ch-497: NEET 2022 Chemistry - Class 12 NEET-2022-Ch-497 Solution: Two half cell reactions are given below. \(Co^{3+} + e^-…

Two half cell reactions are given below. Co3++e−→Co2+ECo2+/Co3+∘=−1.81 VCo^{3+} + e^- \rightarrow Co^{2+} E_{Co^{2+}/Co^{3+}}^\circ = -1.81\ \text{V} 2Al3++6e−→2Al(s)EAl/Al3+∘=+1.66 V2Al^{3+} + 6e^- \rightarrow 2Al(s) E_{Al/Al^{3+}}^\circ = +1.66\ \text{V} The standard EMF of a cell with feasible redox reaction will be: -3.47 V +7.09 V +0.15 V +3.47 V

Multiple Choice Options

  • A −- _ 3.47 V
  • B +7.09 V
  • C +0.15 V
  • D +3.47 V

Step-by-Step Verified Solution

Since E O P 0 of Al is more than Co 2+ , so at anode Al will oxidise and at cathode Co 3+ will reduce. E C e l l 0 = ( E C a t h o d e 0 ) R P _ ( E A n o d e 0 ) R P = E C o 3 + / C o 2 + 0 _ E A l 3 + / A l 0 = ( 1.81 ) _ ( _ 1.66 ) = + 3.47 V

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