Verified Solution • 2025–26 Session moderate

QNEET-2022-Ch-491: NEET 2022 Chemistry - Class 12 NEET-2022-Ch-491 Solution: \(Na_2B_4O_7 { } X + NaBO_2\) in the above reaction the product …

Na2B4O7→ΔX+NaBO2Na_2B_4O_7 \xrightarrow{\Delta} X + NaBO_2 in the above reaction the product "X" is: NaB3O5NaB_3O_5 H3BO3H_3BO_3 B2O3B_2O_3 Na2B2O5Na_2B_2O_5

Multiple Choice Options

  • A NaB 3 O 5
  • B H 3 BO 3
  • C B 2 O 3
  • D Na 2 B 2 O 5

Step-by-Step Verified Solution

Na 2 B 4 O 7 _ _ B 2 O 3 + 2NaBO 2 Product X is B 2 O 3

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