Verified Solution • 2025–26 Session moderate

QNEET-2022-Ch-490: NEET 2022 Chemistry - Class 11 NEET-2022-Ch-490 Solution: If first ionization enthalpies of elements X and Y are \(419\…

If first ionization enthalpies of elements X and Y are 419 kJ mol−1419\ \text{kJ mol}^{-1} and 590 kJ mol−1590\ \text{kJ mol}^{-1} respectively and second ionization enthalpies of X and Y are 3069 kJ mol−13069\ \text{kJ mol}^{-1} and 1145 kJ mol−11145\ \text{kJ mol}^{-1} respectively. Then correct statement is: Both X and Y are alkaline earth metals X is an alkali metal and Y is an alkaline earth metal X is an alkaline earth metal and Y is an alkali metal Both X and Y are alkali metals

Multiple Choice Options

  • A Both X and Y are alkaline earth metals
  • B X is an alkali metal and Y is an alkaline earth metal
  • C X is an alkaline earth metal and Y is an alkali metal
  • D Both X and Y are alkali metals

Step-by-Step Verified Solution

As it can be observed from given data of question, in case of element 'X' there is huge difference between IP 1 and IP 2 hence it will have one electron in outermost shell and will be alkali metal. While for 'Y' difference is not that high hence it will be alkaline earth metal.

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