Verified Solution • 2025–26 Session moderate

QNEET-2021-Ph-644: NEET 2021 Physics - Class 11 NEET-2021-Ph-644 Solution: A car starts from rest and accelerates at \(5\ {m/s}^2\). At t…

A car starts from rest and accelerates at 5 m/s25\ \text{m/s}^2. At t = 4 s a ball is dropped out of a window by a person sitting in the car. What is the velocity and acceleration of the ball at t = 6 s? (Take g = 10 m/s2\text{m/s}^2) 202 m/s20\sqrt{2}\ \text{m/s} 10 m/s2\text{m/s}^2 20 m/s 5 m/s2\text{m/s}^2 20 m/s 0 202 m/s20\sqrt{2}\ \text{m/s}0

Multiple Choice Options

  • A 20 2\sqrt 2 2 _ m/s, 10 m/s 2
  • B 20 m/s, 5 m/s 2
  • C 20 m/s, 0
  • D 20 2\sqrt 2 2 _ m/s, 0

Step-by-Step Verified Solution

u = 0 a = 5 t = 4 velocity of car at t = 4 sec is V = u + at V = 0 + 5 _ 4 V = 20 m/s For ball : At t = 4 s, A ball is dropped out of a window so velocity of ball at this instant is 20 ms�1 along horizontal. After 2 seconds of motion : Horizontal velocity of ball , V x = 20 m/sec V y = u + ut = 10 _ 2 Vertical velocity of ball, V y = 20 m/sec So magnitude of velocity of ball V = V x 2 + V y 2 = 20 2 and Acceleration of ball at t = 6 s is g = 10 m/sec 2 As ball is under free fall.

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