Verified Solution • 2025–26 Session moderate

QNEET-2021-Ph-643: NEET 2021 Physics - Class 11 NEET-2021-Ph-643 Solution: From a circular ring of mass 'M' and radius 'R' an arc…

From a circular ring of mass 'M' and radius 'R' an arc corresponding to a

90^\circ

sector is removed. The moment of inertia of the remaining part of the ring about an axis passing through the center of the ring and perpendicular to the plane of the ring is 'K' times '

MR^2

'. Then the value of 'K' is:

1/8

3/4

7/8

1/4

Multiple Choice Options

A ${1 \over 8}$ 8 1 _
B ${3 \over 4}$ 4 3 _
C ${7 \over 8}$ 8 7 _
D ${1 \over 4}$ 4 1 _

Step-by-Step Verified Solution

Given that, Mass of Ring = M; Radius of Ring = R Now 90� arc is removed from circular ring, then Mass removed = M 4 _ Mass of remaining portion = 3 M 4 I = MR 2 I' = 3 M 4 R 2 I' = 3 4 I _ K = 3 4

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