Verified Solution • 2025–26 Session moderate

QNEET-2021-Ph-640: NEET 2021 Physics - Class 11 NEET-2021-Ph-640 Solution: A particle of mass 'm' is projected with a velocity \(v =…

A particle of mass 'm' is projected with a velocity v=kVev = kV_e (k < 1) from the surface of the earth. (VeV_e = escape velocity) The maximum height above the surface reached by the particle is: Rk21−k2\frac{Rk^2}{1-k^2} R(k1−k)2R(\frac{k}{1-k})^2 R(k1+k)2R(\frac{k}{1+k})^2 R2k1+k\frac{R^2k}{1+k}

Multiple Choice Options

  • A Rk21−k2{{R{k^2}} \over {1 - {k^2}}} 1 _ k 2 R k 2 _
  • B R(k1−k2)2R{\left( {{k \over {1 - {k^2}}}} \right)^2} R ( 1 _ k 2 k _ ) 2
  • C R(k1+k2)2R{\left( {{k \over {1 + {k^2}}}} \right)^2} R ( 1 + k 2 k _ ) 2
  • D R2k1+k{{{R^2}k} \over {1 + k}} 1 + k R 2 k _

Step-by-Step Verified Solution

_ G M m R + 1 2 m k 2 v e 2 = _ G M m r _ G M m R + 1 2 m k 2 2 G M R = _ G M m r _ 1 R + k 2 R = _ 1 r 1 r = 1 R _ k 2 R 1 r = 1 _ k 2 R r = R 1 _ k 2 R + h = R 1 _ k 2 h = R 1 _ k 2 _ R = k 2 1 _ k 2 R

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