Verified Solution • 2025–26 Session moderate

QNEET-2021-Ph-632: NEET 2021 Physics - Class 11 NEET-2021-Ph-632 Solution: A particle is released from height S from the surface of the…

A particle is released from height S from the surface of the Earth. At a certain height its kinetic energy is three times its potential energy. The height from the surface of earth and the speed of the particle at that instant are respectively - S43gS2\frac{S}{4} \frac{\sqrt{3gS}}{2} S43gS2\frac{S}{4} \frac{\sqrt{3gS}}{2} S43gS2\frac{S}{4} \sqrt{\frac{3gS}{2}} S23gS2\frac{S}{2} \sqrt{\frac{3gS}{2}}

Multiple Choice Options

  • A S4,3gS2{S \over 4},\sqrt {{{3gS} \over 2}} 4 S _ , 2 3 g S _ _
  • B S4,3gS2{S \over 4},{{3gS} \over 2} 4 S _ , 2 3 g S _
  • C S4,3gS2{S \over 4},{{\sqrt {3gS} } \over 2} 4 S _ , 2 3 g S _ _
  • D S2,3gS2{S \over 2},{{\sqrt {3gS} } \over 2} 2 S _ , 2 3 g S _ _

Step-by-Step Verified Solution

PE + KE = mgs at given point KE = 3PE So, 4PE = mgs 4mgh = mgs H = s/4 KE = 3 m g s 4 = 1 2 mV 2 V = 3 g s 4 = 3 g s 2

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