Verified Solution • 2025–26 Session moderate

QNEET-2021-Ph-630: NEET 2021 Physics - Class 12 NEET-2021-Ph-630 Solution: In the product \( {F} = q( {v} {B}) = q {v} (B {i} + B {j} +…

In the product F⃗=q(v⃗×B⃗)=qv⃗×(Bi^+Bj^+B0k^)\vec{F} = q(\vec{v} \times \vec{B}) = q\vec{v} \times (B\hat{i} + B\hat{j} + B_0\hat{k}) For q = 1 and v⃗=2i^+4j^+6k^\vec{v} = 2\hat{i} + 4\hat{j} + 6\hat{k} and F⃗=4i^−20j^+12k^\vec{F} = 4\hat{i} - 20\hat{j} + 12\hat{k} What will be the complete expression for B⃗\vec{B}? 6i^+6j^−8k^6\hat{i} + 6\hat{j} - 8\hat{k} −8i^−8j^−6k^-8\hat{i} - 8\hat{j} - 6\hat{k} −6i^−6j^−8k^-6\hat{i} - 6\hat{j} - 8\hat{k} 8i^+8j^−6k^8\hat{i} + 8\hat{j} - 6\hat{k}

Multiple Choice Options

  • A 6i^+6j^−8k^6\widehat i + 6\widehat j - 8\widehat k 6 i + 6 j _ _ 8 k
  • B −8i^−8j^−6k^- 8\widehat i - 8\widehat j - 6\widehat k _ 8 i _ 8 j _ _ 6 k
  • C −6i^−6j^−8k^- 6\widehat i - 6\widehat j - 8\widehat k _ 6 i _ 6 j _ _ 8 k
  • D 8i^+8j^−6k^8\widehat i + 8\widehat j - 6\widehat k 8 i + 8 j _ _ 6 k

Step-by-Step Verified Solution

Given q = 1 and v _ = 2 i ^ + 4 j ^ + 6 k ^ and F _ = 4 i ^ _ 20 j ^ + 12 k ^ Also given, F _ = q ( v _ _ B _ ) = q v _ _ ( B i ^ + B j ^ + B 0 k ^ ) _ ( 4 i ^ _ 20 j ^ + 12 k ^ ) = _ 1 _ [ ( 2 i ^ + 4 j ^ + 6 k ^ ) _ ( B i ^ + B j ^ + B 0 k ^ ) ] Thus, calculating values of RHS, v _ _ B _ = | i ^ j ^ k ^ 2 4 6 B B B 0 | = i ^ (4B 0 - 6B) - j ^ (2B 0 - 6B) + k ^ (2B - 4B) Comparing L.H.S and R.H.S, 4B 0 � 6B = 4 .....(1) �(2B 0 � 6B)= �20 .....(2) 2B � 4B = 12 _ B = �6 .....(3) From (2) and (3) B = �6 and B 0 = �8 _ B _ = _ 6 i ^ _ 6 j ^ _ 8 k ^

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