Verified Solution • 2025–26 Session moderate

QNEET-2021-Ph-621: NEET 2021 Physics - Class 11 NEET-2021-Ph-621 Solution: A uniform rod of length 200 cm and mass 500 g is balanced on a…

A uniform rod of length 200 cm and mass 500 g is balanced on a wedge placed at 40 cm mark. A mass of 2 kg is suspended from the rod at 20 cm and another unknown mass 'm' is suspended from the rod at 160 cm mark as shown in the figure. Find the value of 'm' such that the rod is in equilibrium. (g = 10

m/s^2

)

\frac{1}{12}\ \text{kg}

\frac{1}{2}\ \text{kg}

\frac{1}{3}\ \text{kg}

\frac{1}{6}\ \text{kg}

Multiple Choice Options

A ${1 \over {12}}$ 12 1 _ kg
B ${1 \over {2}}$ 2 1 _ kg
C ${1 \over {3}}$ 3 1 _ kg
D ${1 \over {6}}$ 6 1 _ kg

Step-by-Step Verified Solution

By balancing torque 2g _ 20 = 0.5g _ 60 + mg _ 120 _ m = 0.5 6 kg = 1 12 kg

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