Verified Solution • 2025–26 Session moderate

QNEET-2021-Ph-616: NEET 2021 Physics - Class 12 NEET-2021-Ph-616 Solution: An inductor of inductance L a capacitor of capacitance C and a…

An inductor of inductance L a capacitor of capacitance C and a resistor of resistance 'R' are connected in series to an ac source of potential difference 'V' volts as shown in figure. Potential difference across L C and R is 40 V 10 V and 40 V respectively. The amplitude of current flowing through LCR series circuit is

10\sqrt{2}\ \text{A}

. The impedance of the circuit is:

5\Omega

4\sqrt{2}\Omega

5/\sqrt{2}\Omega

4\Omega

Multiple Choice Options

A 5 $\Omega$ �
B 4 $\sqrt 2$ 2 _ $\Omega$ �
C 5/ $\sqrt 2$ 2 _ $\Omega$ �
D 4 $\Omega$ �

Step-by-Step Verified Solution

I 0 = 10 2 A I RMS = I 2 = 10A V R M S = V R 2 + ( V L _ V C ) 2 = ( 40 ) 2 + ( 40 _ 10 ) 2 = 50 V Impedance, Z = V R M S I R M = 50 V 10 V = 5 �

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