Verified Solution • 2025–26 Session moderate

QNEET-2020-Ph-739: NEET 2020 Physics - Class 11 NEET-2020-Ph-739 Solution: A wire of length L area of cross section A is hanging from a…

A wire of length L area of cross section A is hanging from a fixed support. The length of the wire changed to L1L_1 when mass M is suspended from its free end. The expression for Young's modulus is: MgLA(L1−L)\frac{MgL}{A(L_1-L)} MgL1AL\frac{MgL_1}{AL} MgLA(L1−L)\frac{MgL}{A(L_1-L)} MgL1A(L1−L)\frac{MgL_1}{A(L_1-L)}

Multiple Choice Options

  • A Mg(L1−L)AL{{Mg\left( {{L_1} - L} \right)} \over {AL}} A L M g ( L 1 _ _ L ) _
  • B MgLAL1{{MgL} \over {A{L_1}}} A L 1 _ M gL _
  • C MgLA(L1−L){{MgL} \over {A\left( {{L_1} - L} \right)}} A ( L 1 _ _ L ) M gL _
  • D MgL1AL{{Mg{L_1}} \over {AL}} A L M g L 1 _ _

Step-by-Step Verified Solution

S t r e s s = M g A S t r a i n = _ L L = L _ 1 _ L L Young's modulus = S t r e s s S t r a i n = M g L A ( L 1 _ L )

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