Verified Solution • 2025–26 Session moderate

QNEET-2020-Ph-734: NEET 2020 Physics - Class 11 NEET-2020-Ph-734 Solution: The mean free path for a gas with molecular diameter d and…

The mean free path for a gas with molecular diameter d and number density n can be expressed as: 12nπd2\frac{1}{\sqrt{2}n\pi d^2} 12n2πd2\frac{1}{\sqrt{2}n^2\pi d^2} 12n2π2d2\frac{1}{\sqrt{2}n^2\pi^2 d^2} 12nπd\frac{1}{\sqrt{2}n\pi d}

Multiple Choice Options

  • A 12nπd2{1 \over {\sqrt 2 n\pi {d^2}}} 2 _ n� d 2 1 _
  • B 12n2πd2{1 \over {\sqrt 2 {n^2}\pi {d^2}}} 2 _ n 2 � d 2 1 _
  • C 12n2π2d2{1 \over {\sqrt 2 {n^2}{\pi ^2}{d^2}}} 2 _ n 2 � 2 d 2 1 _
  • D 12nπd{1 \over {\sqrt 2 n\pi d}} 2 _ n� d 1 _

Step-by-Step Verified Solution

As per the formula, _ = 1 2 n � d 2

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