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QNEET-2020-Ph-731: NEET 2020 Physics - Class 12 NEET-2020-Ph-731 Solution: In Young's double slit experiment if the separation between…
In Young's double slit experiment if the separation between coherent sources is halved and the distance of the screen from the coherent sources is doubled then the fringe width becomes: half four times one-fourth double
Multiple Choice Options
- A half
- B four times
- C one-fourth
- D double
Step-by-Step Verified Solution
Given that the slit distance is made half and the screen distance made double than the original value, then,
Fringe width, _ = _ D d
Now, d _ = d 2
and D _ = 2 D
So, _ _ = _ ( 2 D ) d / 2 = 4 _ D d
_ = 4 _